x^2-2x-95.04=0

Solution for x^2-2x-95.04=0 equation:

x^2-2x-95.04=0

a = 1; b = -2; c = -95.04;
Δ = b2-4ac
Δ = -22-4·1·(-95.04)
Δ = 384.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{384.16}}{2*1}=\frac{2-\sqrt{384.16}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{384.16}}{2*1}=\frac{2+\sqrt{384.16}}{2}
$